# Force and Motion 2

Team: ____________________

____________________

Force and Motion 2

Part I. Non Constant Force ( A Case Study

How does F(x) depend on x ?

So far in this course, all the forces you have studied have been constant forces ( independent of position. Many forces in nature depend on position. The gravitational force on a planet depends on its distance from the sun. The magnetic force on a mag-lev train depends on its distance from the tracks. In this lab, you will encounter one of the most important position-dependent forces in physics: the force due to a spring. The mechanical system that you will study consists of a cart connected to two springs moving on a metal track:

The origin of the x-axis is chosen to be the point where the net force on the cart is zero. The cart will remain at rest at x = 0. At this so-called “equilibrium point”, the left spring pulls on the cart with a force that exactly balances the pull of the right spring. Thus F = 0 at x = 0. With your hand, pull the cart away from x = 0 to another position, such as x = 5 cm or x = (5 cm and feel the force. The force always restores the mass back toward x = 0:

As you pull the cart further away from x = 0, the restoring force back to x = 0 becomes stronger due to the increasing expansion and compression of the springs. Thus the magnitude of F is not constant: F depends on x.

Since the force F on the cart depends on the position x of the cart, this physical quantity is represented by a mathematical function F(x). Given any value of x, the function F(x) specifies

the value of the force at that particular x. Based on your qualitative study so far, all you know about this function is that F(0) = 0 and that the magnitude of F(x) is an increasing function. Your experimental goal is to find the precise form of this force function. Does F(x) have the form F = 3x , or F = 5x2 , or F(x) = ln(1+x)? You will find F(x) two different ways: (1) Dynamically, by observing the back-and-forth motion of the cart. (2) Statically, by using a spring scale.

1. Discovering the Law of Force

In physics, a force law is a mathematical rule that specifies how force depends on position. From the previous Force and Motion Lab, you learned how physicists discover the force laws of nature: observe the motion, deduce the force. In this experiment, your quest is to

Deduce how the force F(x) depends on x from a measurement of

how the position x(t) depends on t.

For any constant force, the motion is described by a quadratic function of time: x(t) = ½at2. For gravity (near the earth’s surface), the well known value of the constant acceleration is a = 9.8 m/s2. The geometric trademark of constant-force motion is the parabolic shape of the x-t curve. For the non-constant force due to springs, what is the shape of x(t)?

Sinusoidal Motion

Pull the cart from x = 0 to about x = 20 cm and release. Use the motion sensor to record the position x(t) of the cart as a function of time. [Open Logger Pro file Moving Along] Does your x-t curve look like a “sine curve”? A sine it is!

There is a deep connection between force and geometry:

Gravitational Force ( Elliptical Motion

Spring Force ( Sinusoidal Motion

Electromagnetic Force ( Helical Motion

As the cart moves back and forth along the x axis, the motion repeats itself. The cart oscillates or vibrates. The position function x(t) is a periodic function of time t. Oscillatory motion is everywhere in Nature: pendulum, tuning fork, guitar string, sound waves, light waves, radio waves, electron in antenna, atomic clock, molecular vibrations (heat), nuclear magnetic resonance (NMR), pulsating stars (pulsars), oscillating universe (big bang-big crunch).

The mathematical equation describing the x-t curve recorded by your motion sensor is

x(t) = A sin (2(t/T) .

Qualitatively speaking, the parameters A and T specify the “height” and the “width” of the sine curve:

More precisely, the amplitude A is the maximum displacement of the cart away from the equilibrium point. The period T is the time it takes the cart to complete one oscillation (one back-and-forth motion) Note that the function x(t) = Asin(2(t/T) is bounded, (A ( x ( A, and periodic, x(t+T) = x(t).

Examine the x-t curve recorded by your motion sensor. Read off the values of A and T that characterize the sinusoidal motion of your cart:

A = ______________ m . T = ______________ s .

The Period of Motion T Determines the Law of Force F(x)

Amazing Fact: If you know the time T, then you can figure out the force F(x). Here are the key steps that allow you to deduce the force function F(x) from the motion function x(t):

F = m a

= m dv/dt

= m d2 x /dt2

= m d2 Asin(2(t/T) /dt2

= m [((2(/T)2 Asin(2(t/T) ]

= m [((2(/T)2 x ]

Can you justify each step (equal sign)? This derivation illustrates the power of Newton’s physics and calculus in analyzing nature.

The last line in the derivation reveals precisely how F depends on x. In summary, by inserting the motion function x = Asin(2(t/T) into Newton’s law, F = m d2x/dt2 , we have deduced the following force function:

F(x) = ( (4(2m/T2) x .

Physicists write this force law in the form

F = ( kx ,

where the force constant k is

k = 4(2m/T2 .

The magnitude of the force F on the cart increases in direct proportion to the distance x that the cart is displaced from the equilibrium point (x=0). If you double x , then you double F. The constant k is the proportionality constant between F and x. The minus sign in F = (kx indicates that the force is always opposite to the displacement. A cart on the right (left) side of x=0 experiences a force that is directed to the left (right).

Physicists say that the spring force is a “linear force” because the force function F = (kx is a linear function of x. In contrast, the force of gravity and the force of electricity are “inverse-squared forces” (F = k/x2 ). Whereas the spring force gets stronger as the distance increases, the forces of gravity and electricity get weaker as x increases.

If you know the value of the force constant k, then you know everything about the spring force in your system. Different spring systems have different values of k. Stiff springs (car suspensions) have large values of k. Weak springs (toy slinkys) have small values. What is the value of k that characterizes the chemical bond – the electromagnetic spring ( between the vibrating oxygen atoms in an O2 molecule?

Note that k = 4(2m/T2 goes like 1/T2 :

strength of force ( inverse square of period .

Why should the force be related to the inverse of time? This relation makes intuitive sense. A stiff spring (large k) vibrates faster (small T) than a weak spring. If the cart moves back-and forth rapidly (small T), then the velocity changes rapidly (large a), and thus the force (ma) must be strong (large k). Symbolically speaking, F = ma and a = d2x/dt2, and thus roughly speaking, F goes like 1/(dt)2 .

Measuring the Force Constant with a Stopwatch

Bottom Line: To find the law of force F(x) = ( (4(2m/T2)x , you need to measure the mass m of the cart and the period T of the motion.

Measure the mass of the cart. m = ________________ kg .

Measure the period with a stopwatch. More specifically, measure the time it takes for the cart to complete five oscillations (five back-and-forth motions). Divide this five-cycle time by five to obtain the period. Why five? Ten would be good too. Because of the uncertainty in starting and stopping the watch and counting the oscillations, it is more accurate to measure a long time rather than a short time. For example, if the uncertainty in measuring the time with the

stopwatch is 0.5 seconds, then the measurement 5 ( 0.5 seconds is a 10% error, whereas the measurement 50 ( 0.5 seconds is only a 1% error. Report the value of the period of your oscillating cart.

T = _______________ s .

Is this stopwatch value of T consistent with (within 5% of) the graphical value of T that you obtained from the “width” of your x-t curve?

Based on your measured values of m and T, what is the force constant that characterizes your spring system? Show your calculation.

k = _________________ N/m.

Given this value of k, compute the magnitude of the force (F = ( kx without the minus sign) at those values of x listed in the following table.

Force deduced from the Motion

|x (m) |0 |0.02 |0.04 |0.06 |0.08 |

|N (Newtons) | | | | | |

|f (Newtons) | | | | | |

Use the program Graphical Analysis to graph f versus N (f on y axis, N on x axis). Find the best-fit line through you five data points. If you compare the mathematical equation of a line “y = mx+b” with the physical equation of friction, written in the form “f = (N+0”, then it follows that the coefficient of friction ( is equal to the slope (m) and the y-intercept (b) should be zero. Indeed, ( = f/N is the rise over the run of the line. Print your graph showing the best-fit line and the value of the slope. Report your measured value of the coefficient of friction:

( = _______________ (felt on aluminum).

Since one measurement of ( is subject to error, lets average the results of several experiments to obtain an accurate value of (. Write your value of ( on the chalkboard. In the space below, list the values of ( obtained by the other teams in the class. Compute the class average and the uncertainty.

( = ______________ ( ______________ (felt on aluminum).

Part III. Experimental Design: Lowering a Weight at g/30

Your goal is to lower a “heavy” weight (100 gram brass cylinder) over a pulley so that the weight falls to the ground with an acceleration that is 1/30 that of free fall. Here is the schematic of the mechanical system:

The Theory

Work out the theory in the space below. Draw free-body diagrams and set up Newton’s equation of motion for each body. Derive the theoretical equation that gives the acceleration a of the system as a function of the system parameters: mL , mB , mH , ( , and g. Hint: treat the Block and the Load as one mass (m ( mB + mL) and draw two free body diagrams, one for m and one for mH.

a = _______________________________________ .

Into this theoretical equation, plug your measured values of mB and ( , the well known value of g, and the design specifications for mH and a. Solve the resulting equation for the predicted value of the load mass mL. Show all your work.

mL = ___________________ kg .

The Experiment

First make sure that the track is level using the leveler. Add the predicted amount of load mL to the block. Distribute the load weights evenly over the top of the block. Release the system from rest and measure the acceleration.

Report your measured value of a. Include the uncertainty in a. Describe how you made the measurement and estimated the uncertainty. Provide all data and/or graphs that you used to find a.

a (measured) = ________________ ( ________________ m/s2 .

Compare your value of a(measured) with the design goal of a = g/30. What is the percent difference? Write down the range of experimental numbers that characterize your measured acceleration. Does the theoretical number g/30 fall within this range?

-----------------------

5

x = 0

F

F

0

F

F

0

N

Fs(x) =

2A

t

T

mg

(5

v = constant

F (scale)

f (friction)

Load

mL

mB

Block

Felt

Aluminum

Hanging Mass

mH = 100 grams

g/30

F(x) =

x

x

x

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