RTI requires progress monitoring to occur on a consistent basis to gauge the relevance and success of universal, targeted, and intensive individualized interventions being implemented
RTI requires progress monitoring to occur on a consistent basis to gauge the relevance and success of universal, targeted, and intensive individualized interventions being implemented
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RTI requires progress monitoring to occur on a consistent basis to gauge the relevance and success of universal, targeted, and intensive individualized interventions being implemented. Data analysis allows teachers to make relevant decisions about individual students and advocate for new or continued placement on the RTI continuum.
Review the “Analyzing Student Data: RTI Model Student Progress Monitoring Scenario” to inform the assignment.
In a 500‐750 word analysis, complete the following:
- Summary of overall student progress.
- Interpret the data to determine whether Janet is responding adequately to Tier 2 instruction.
- Why you think the support team members disagree about what tier of instruction would best meet Janet’s needs. Rationalize your answer.
- Tier of instruction you would recommend for Janet: Tier 1 instruction only, another round of Tier 2 instruction, or intensive Tier 3 instruction? Explain your answer.
Support your analysis with 2‐3 scholarly resources.
Prepare this assignment according to the guidelines found in the APA Style Guide, located in the Student Success Center. An abstract is not required.
This assignment uses a rubric. Review the rubric prior to beginning the assignment to become familiar with the expectations for successful completion.
You are required to submit this assignment to LopesWrite. Refer to the LopesWrite Technical Support articles for assistance.
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Analyzing Student Data:
RTI Model Student Progress Monitoring Scenario
Student Name: Janet
Age: 9
Grade: 4
Janet is currently a fourth grader at Bellmont Elementary School. Janet’s teacher, Ms. Clay, began adding Tier 2 instruction for her after Janet’s Lexile reader measure level was 545L in the seventh week of the school year compared to the average peer Lexile level of 790 in her class. This score confirmed the concerns of Ms. Clay regarding Janet’s difficulty with reading comprehension. Ms. Clay has been monitoring her progress using district-wide curriculum-based measurements. After 10 weeks of Tier 2 instruction (mid-school year), Janet’s Lexile Stretch goal is 605L and her expected rate of growth (slope) is 5.0.
The school-based student support team met last week to review Janet’s progress following the Tier 2 instruction that had been implemented. The purpose of the meeting was to determine what tier of instruction would best meet Janet’s current educational needs in reading comprehension based on the progress monitoring data that was collected. The team analyzed progress and compared Janet’s current reading levels to those of same-age peers to determine if she has been responding to the targeted Tier 2 instruction. After reviewing the results, the school-based student support team members disagree about what tier of instruction should now be used to further develop Janet’s reading comprehension skills and help her reach grade level on the Lexile assessment.
Target Lexile Scores
GRADE | College and Career Ready“Stretch” Lexile Bands |
1 | 190L to 530L |
2 | 420L to 650L |
3 | 520L to 820L |
4 | 740L to 940L |
5 | 830L to 1010L |
6 | 925L to 1070L |
7 | 970L to 1120L |
8 | 1010L to 1185L |
Janet’s Lexile Scores:
Week of Tier 2 instruction | Janet’s Current Assessed Level | Janet’s Goal |
Janet’s Initial Base score | 545 | —– |
1(Tier 2 instruction began) | 545 | 550 |
2 | 545 | 555 |
3 | 550 | 560 |
4 | 550 | 560 |
5 | 555 | 570 |
6 | 560 | 570 |
7 | 555 | 580 |
8 | 560 | 585 |
9 | 570 | 590 |
10 | 580 | 590 |
Using the slope calculator or calculating on paper to determine rate of progress (slope) for Janet, it is determined that her slope is 4.44 with a goal of 5.0.
Subtract first and last score: 590-550 = 40
Subtract the week of instructions: Week 10-Week 1 = 9
Divide the score by the result of the week of instruction: 40/9 = 4.44
Janet’s slope is 4.44
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